I wanna show you what happens if you do a postback inside a modal jQuery UI dialog. This is a problem I had some times ago making this challenge on Cloudspokes.
We have a simple controller:
public class MyController { public String value{get;set;} public void anAction() { if(value != null && value.length()>0) ApexPages.addMessage(new ApexPages.Message(ApexPages.Severity.ERROR ,'Variable set to ['+value+']')); else ApexPages.addMessage(new ApexPages.Message(ApexPages.Severity.ERROR ,'Variable not set')); } }
And this is the Visualforce page:
<apex:page controller="MyController" id="myPage"> <apex:includeScript value="{!URLFOR($Resource.UIJQuery1822, 'js/jquery-1.7.2.min.js')}"/> <apex:includeScript value="{!URLFOR($Resource.UIJQuery1822, 'js/jquery-ui-1.8.22.custom.min.js')}"/> <apex:stylesheet value="{!URLFOR($Resource.UIJQuery1822, 'css/ui-lightness/jquery-ui-1.8.22.custom.css')}"/> <script language="javascript"> //escapes Visualforce ID for jQuery function esc(myid) { return '#' + myid.replace(/(:|.)/g,'$1'); } j$ = jQuery.noConflict(); //opens the dialog function openDialog(dialogId) { j$(esc(dialogId)).dialog({title:'Dialog window', modal:true}); } //copies value from an input to another function copyHiddenFields(fromId, toId) { j$(esc(toId)).val(j$(esc(fromId)).val()); } </script> <apex:form id="myForm"> <apex:pageMessages /> <apex:outputPanel id="__dialog" style="display:none;"> <apex:inputtext value="{!value}"/> <apex:commandButton value="Submit" action="{!anAction}"/> </apex:outputPanel> <apex:commandButton value="Open popup" onClick="openDialog('{!$Component.__dialog}'); return false;"/> </apex:form> </apex:page>
This is the result:
If you try to post back nothing happens.
This is because the dialog is detached from the body and in some way the command button is detached from the javascript that makes the postback.
The trick is to use an <apex:actionFunction> component:
<apex:actionFunction action="{!anAction}" name="doPostback"/> <apex:outputPanel id="__dialog2" style="display:none;"> <apex:outputPanel > <apex:inputtext value="{!value}"/> <apex:commandButton onclick="doPostback(); return false;" value="Submit"/> </apex:outputPanel> </apex:outputPanel> <apex:commandButton value="Open popup 2" onClick="openDialog('{!$Component.__dialog2}'); return false;"/>
Now the postback works but there is still a problem: the “value” field is never set: the postback doesn’t send any field in the dialog.
To accomplish this, you have to use an helper hidden field and some javascript to copy the dialog field into the hidden field (which is outside the dialog):
<apex:actionFunction action="{!anAction}" name="doPostback"/> <apex:inputHidden value="{!value}" id="inputHidden"/> <apex:outputPanel id="__dialog3" style="display:none;"> <apex:outputPanel > <apex:inputtext id="inputText" value="{!value}"/> <apex:commandButton onclick="copyHiddenFields('{!$Component.inputText}','{!$Component.inputHidden}'); doPostback(); return false;" value="Submit"/> </apex:outputPanel> </apex:outputPanel> <apex:commandButton value="Open popup 3" onClick="openDialog('{!$Component.__dialog3}'); return false;"/>
Append this simple JS function in the “script” tags:
//copies value from an input to another function copyHiddenFields(fromId, toId) { j$(esc(toId)).val(j$(esc(fromId)).val()); }
Now the postback sends the correct value to the controller.
I leave you with a song for your soul.
oski1993
Very cool… what is causing the 'parent' page to refresh though after submission from the dialog box. Is it due to the action function?
I'm wanting to do this from a controller extension class. I'm hoping not to refresh the parent page because there are other fields on the page that may have been edited but not yet saved. The value entered into the dialog box is not needed to be displayed on the parent page at all.
I'm ideally hoping to 'asynchronously' save the value from the dialog box back to the database independently with the only change to the parent page being a 'Save successful/failed' message.
Thanks!